(w^2-2w-24)/(5w^2-80)

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Solution for (w^2-2w-24)/(5w^2-80) equation: 


D( w )

5*w^2-80 = 0

5*w^2-80 = 0

5*w^2-80 = 0

5*w^2 = 80 // : 5

w^2 = 16

w^2 = 16 // ^ 1/2

abs(w) = 4

w = 4 or w = -4

w in (-oo:-4) U (-4:4) U (4:+oo)

(w^2-(2*w)-24)/(5*w^2-80) = 0

(w^2-2*w-24)/(5*w^2-80) = 0

w^2-2*w-24 = 0

w^2-2*w-24 = 0

DELTA = (-2)^2-(-24*1*4)

DELTA = 100

DELTA > 0

w = (100^(1/2)+2)/(1*2) or w = (2-100^(1/2))/(1*2)

w = 6 or w = -4

(w+4)*(w-6) = 0

((w+4)*(w-6))/(5*w^2-80) = 0

( w+4 )

w+4 = 0 // - 4

w = -4

( w-6 )

w-6 = 0 // + 6

w = 6

w in { -4} 

w = 6

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